How do you simplify #(3 + 3i) - (4 - 3i)#?
6i - 1
When adding or subtracting Complex numbers together the following approach is used:
(a + bi ) + (c + di ) = ( a + c) + ( b + d ) i
ie. We add the real parts together separately from the imaginary parts. The same applies when subtracting.
in the question given then:
(3 + 3i ) - (4 - 3i ) removing the brackets gives 3 + 3i - 4 + 3i
and applying the above gives (3 - 4 ) + (3 + 3 )i = - 1 + 6i = 6i - 1