# How do you simplify (3b)/(-5c^-1) and write it using only positive exponents?

Jul 23, 2017

$\frac{3 b c}{- 5}$ or $- \frac{3 b c}{5}$

#### Explanation:

${x}^{-} a$ generally equates to $\frac{1}{x} ^ a$, so:
$\frac{1}{c} ^ - 1 = {\left({c}^{-} 1\right)}^{-} 1$

$= {c}^{- 1 \setminus \cdot \left(- 1\right)}$ applying exponential multiplication
$= {c}^{1}$ simplified; also equals $c$

replacing into original:

$\frac{3 b}{- 5 {c}^{-} 1}$
$\frac{3 b c}{- 5}$ or $- \frac{3 b c}{5}$