# How do you simplify #(3i)*2+(2i)#?

##### 1 Answer

Aug 6, 2016

#### Explanation:

Complex numbers are just like any other numbers -- just treat

The first thing to do, according to the order of operations, is multiply.

#overbrace((3i)*2)^("multiply first")+(2i)#

Since

#=6i+2i#

From here, add this like you would for

#=i(6+2)#

#=i*8#

#=8i#