How do you simplify #(-3i) (3i) - (2+2i)#?
1 Answer
Jul 6, 2016
7 - 2i
Explanation:
We require to know the following fact.
#color(orange)"Reminder"#
#color(red)(|bar(ul(color(white)(a/a)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(a/a)|)))#
#rArr(-3i)(3i)=-9i^2=(-9xx-1)=9# hence
#(-3i)(3i)-(2+2i)=9-2-2i=7-2i#
