How do you simplify (3x^2-3x-6)/(x^2-4)3x23x6x24?

1 Answer
May 12, 2018

(3(x+1))/(x+2)3(x+1)x+2

Explanation:

"factorise the numerator/denominator and "factorise the numerator/denominator and
"cancel any common factors"cancel any common factors

color(magenta)"factor numerator"factor numerator

"take out a "color(blue)"common factor "3take out a common factor 3

rArr3(x^2-x-2)3(x2x2)

"the factors of - 2 which sum to - 1 are - 2 and + 1"the factors of - 2 which sum to - 1 are - 2 and + 1

=3(x-2)(x+1)=3(x2)(x+1)

color(magenta)"factor denominator"factor denominator

x^2-4" is a "color(blue)"difference of squares"x24 is a difference of squares

•color(white)(x)a^2-b^2=(a-b)(a+b)xa2b2=(ab)(a+b)

rArrx^2-4=x^2-2^2=(x-2)(x+2)x24=x222=(x2)(x+2)

rArr(3x^2-3x-6)/(x^2-4)3x23x6x24

=(3cancel((x-2))(x+1))/(cancel((x-2))(x+2))

=(3(x+1))/(x+2)

"with restriction "x!=-2