How do you simplify $(3x^2+6y)/(3x^2+9x)$ ?

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Answer 1 · 2015-09-25T21:24:08

$(x^2 + 2y)/(x*(x + 3)$

$(3x^2 +6y)/(3x^2 +9x)$

Factor out 3 from numerator, and 3x from the denominator:
$=(3*x^2 + (3*2)y)/(3x*x + 3*3x)$
$=(3*(x^2 + 2y))/(3x*(x + 3))$

Then cancel out the 3 from the numerator and the denominator:
$=(cancel 3*(x^2 + 2y))/(cancel 3 x*(x + 3))$

So you have:
$=(x^2 + 2y)/(x*(x + 3)$

How do you simplify (3x^2+6y)/(3x^2+9x)(3x^2+6y)/(3x^2+9x)?