How do you simplify #(3y)/(3y^2-6y)#?

2 Answers
Apr 6, 2018

Answer:

#=1/(y-2)#

Explanation:

#(3y)/(3y^2-6y)#

#=(3y)/(3y(y-2))# factorise the denominator, HCF#=3y#

#=1/(y-2)# divide numerator and denominator by #3y#

Apr 6, 2018

Answer:

#1/(y-2)#

Explanation:

#(3y)/(3y^2-6y)#

First, we factor the bottom:
#(3y)/(3y(y-2)#

Since both the numerator and denominator are multiplied by #3y#, we can cross that out:
#(cancel(3y))/(cancel(3y)(y-2))#

So the final answer is:
#1/(y-2)#