# How do you simplify (3y)/(3y^2-6y)?

Apr 6, 2018

$= \frac{1}{y - 2}$

#### Explanation:

$\frac{3 y}{3 {y}^{2} - 6 y}$

$= \frac{3 y}{3 y \left(y - 2\right)}$ factorise the denominator, HCF$= 3 y$

$= \frac{1}{y - 2}$ divide numerator and denominator by $3 y$

Apr 6, 2018

$\frac{1}{y - 2}$

#### Explanation:

$\frac{3 y}{3 {y}^{2} - 6 y}$

First, we factor the bottom:
(3y)/(3y(y-2)

Since both the numerator and denominator are multiplied by $3 y$, we can cross that out:
$\frac{\cancel{3 y}}{\cancel{3 y} \left(y - 2\right)}$

$\frac{1}{y - 2}$