# How do you simplify (-4-12i)-(3+8i)+8?

I found: $1 - 20 i$
$- 4 - 12 i \textcolor{red}{- 3 - 8 i} + 8 =$
$= \left(- 4 - 3 + 8\right) + \left(- 12 i - 8 i\right) =$
$= 1 - 20 i$