# How do you simplify (4-2i)(2-i)?

Aug 21, 2016

$6 - 8 i$

#### Explanation:

$4 \times 2 = 8$

$4 \times \left(- i\right) = - 4 i$

$- 2 i \times 2 = - 4 i$

$- 2 i \times \left(- i\right) = + 2 {i}^{2}$

But $i = \sqrt{- 1}$, so ${i}^{2} = - 1$ and

$8 - 4 i - 4 i + 2 \times \left(- 1\right) = 6 - 8 i$