Question

How do you simplify `(4 + 2i)(3 - i)` and write in a+bi form?

Answer 1

When simplified it is: `14+2i`

Explanation:

`(4+2i)*(3-i)=12-4i+6i-2i^2=12+2i+2=14+2i`

Muliplying complex numbers is similar to multiplying real numbers or expressions like `(ax+by)*(cx+dy)` with unknowns `x` and `y`. Only difference to remember is that `i^2=-1`