How do you simplify #(4-3i)(2-i)#?
1 Answer
Aug 23, 2016
5 - 10i
Explanation:
distribute the brackets using, for example, the FOIL method.
#rArr(4-3i)(2-i)=8-10i+3i^2#
#color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(a/a)|)))#
#rArr8-10i+3i^2=5-10i#
#rArr(4-3i)(2-i)=5-10i#
