How do you simplify (4-3i)(2-i)?

Aug 23, 2016

5 - 10i

Explanation:

distribute the brackets using, for example, the FOIL method.

$\Rightarrow \left(4 - 3 i\right) \left(2 - i\right) = 8 - 10 i + 3 {i}^{2}$

$\textcolor{\mathmr{and} a n \ge}{\text{Reminder }} \textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{{i}^{2} = {\left(\sqrt{- 1}\right)}^{2} = - 1} \textcolor{w h i t e}{\frac{a}{a}} |}}}$

$\Rightarrow 8 - 10 i + 3 {i}^{2} = 5 - 10 i$

$\Rightarrow \left(4 - 3 i\right) \left(2 - i\right) = 5 - 10 i$