# How do you simplify #(4+4i)(3+5i)#?

##### 1 Answer

Feb 14, 2016

- 8 + 32i

#### Explanation:

distribute the brackets usingFOIL ( or any method you have )

hence ( 4 + 4i )(3 + 5i )

# = 12 + 20i + 12i + 20i^2 # [ note:

# i^2 = (sqrt-1)^2 = -1 # ]hence :

# 12 + 20i + 12i - 20 = - 8 +32i#