How do you simplify (4+4i)(3+5i)?

Feb 14, 2016
• 8 + 32i

Explanation:

distribute the brackets usingFOIL ( or any method you have )

hence ( 4 + 4i )(3 + 5i ) $= 12 + 20 i + 12 i + 20 {i}^{2}$

[ note: ${i}^{2} = {\left(\sqrt{-} 1\right)}^{2} = - 1$ ]

hence : $12 + 20 i + 12 i - 20 = - 8 + 32 i$