# How do you simplify 4i(6-i) and write the complex number in standard form?

THe answer is $4 + 24 i$
$4 i \left(6 - i\right) = 24 i - 4 {i}^{2}$
As ${i}^{2} = - 1$
so we have the following result $24 i + 4 = 4 + 24 i$