How do you simplify #4root3(135)#?

1 Answer
May 1, 2017

Answer:

See the solution process below:

Explanation:

We can use this rule for radicals to rewrite the expression:

#root(n)(a * b) = root(n)(a) * root(n)(b)#

#4root(3)(135) = 4root(3)(27 * 5) = 4root(3)(27)root(3)(5)#

We can now simplify #root(3)(27) = 3# to write:

#4root(3)(27)root(3)(5) = (4 * 3)root(3)(5) = 12root(3)(5)#