# How do you simplify (4x^0y^-2z^3)/(4x) and write it using only positive exponents?

Jun 3, 2018

$\frac{{z}^{3}}{x {y}^{2}}$

#### Explanation:

$\frac{4 {x}^{0} {y}^{-} 2 {z}^{3}}{4 x}$

Remove ${x}^{0}$,

$\frac{4 {y}^{-} 2 {z}^{3}}{4 x}$

Bring negative exponents down to form positive exponents,

$\frac{4 {z}^{3}}{4 x {y}^{2}}$

Simplify,

$\frac{{z}^{3}}{x {y}^{2}}$

:D