# How do you simplify ((4x)/y^3)^-3?

May 10, 2016

${y}^{9} / \left(64 {x}^{3}\right)$

#### Explanation:

Consider the example ${b}^{- 1}$.; This can be written as $\frac{1}{b}$

Basically the negative exponent turns 'upside down' the elements it is applied to. In this case it is everything inside the brackets.

${\left(\frac{4 x}{y} ^ 3\right)}^{- 3} \text{ " ->" } {\left({y}^{3} / \left(4 x\right)\right)}^{3}$

Notice that in turning it all upside down the exponent of -3 becomes +3

$\frac{{\left({y}^{3}\right)}^{3}}{{\left(4 x\right)}^{3}} = {y}^{9} / \left(64 {x}^{3}\right)$