How do you simplify #(5/6)/(1 1/4)#?

3 Answers
Jan 8, 2017

#(5/6)/(1 1/4)=2/3#

Explanation:

Let us first convert mixed fraction #1 1/4# into improper fraction

#1 1/4=1+1/4=4/4+1/4=5/4#

Now dividing by a fraction #a/b# is equivalent to multiplying by its reciprocal #b/a#

Hence #(5/6)/(1 1/4)#

= #(5/6)/(5/4)#

= #5/6xx4/5#

= #cancel5/(cancel6^3)xx(cancel4^2)/cancel5#

= #2/3#

Jul 7, 2017

#2/3#

Explanation:

To divide and multiply, you need to work with common fractions, so change any mixed number into an improper fraction.

#1 1/4 = (4xx1 +1)/4 = 5/4#

There is a useful technique for dividing fractions given in this form:

#(color(green)(a/b))/(color(magenta)(c/d)) = color(green)(a/b) div color(magenta)(c/d) = a/b color(magenta)(xx d/c) = (ad)/(bc)#

#:.(color(red)(5)/color(blue)(6))/(color(blue)(5)/color(red)(4)) = color(red)(5xx4)/(color(blue)(6xx5))" "larr# now simplify

#(cancel5xxcancel4^2)/(cancel6^3xxcancel5) = 2/3#

Use the complex fraction theorem

Explanation:

# (5/6)/ ( 1 1/4) = (5/6)/(5/4) " "larr( 1 1/4 = 4/4 + 1/4 = 5/4)#

Using the multiplicative inverse and the multiplication property of equality multiply both the top fraction and the bottom fraction by the reciprocal of the bottom fraction # 4/5 #

# (5/6 xx 4/5)/ (5/4 xx 4/5 )" "larr" " 5/4 xx 4/5 = 1" "# leaving

# 5/6 xx 4/5 #

#= 20/30#

#= 2/3#