How do you simplify #(5 - 8y)^2#?
1 Answer
Apr 27, 2017
Explanation:
Each term in the second bracket is multiplied by each term in the first bracket as shown below.
#(5-8y)^2=(5-8y)(5-8y)#
#rArr(color(red)(5-8y))(5-8y)#
#=color(red)(5)(5-8y)color(red)(-8y)(5-8y)#
#=(color(red)(5)xx5)+(color(red)(5)xx-8y)+(color(red)(-8y)xx5)+(color(red)(-8y)xx-8y)#
#=25+(-40y)+(-40y)+64y^2#
#=25-40y-40y+64y^2#
#=64y^2-80y+25larrcolor(red)" in standard form"#
