How do you simplify #(5)/(x-3) + (x)/(x^2-9)#? Algebra Rational Equations and Functions Division of Polynomials 1 Answer Cesareo R. May 13, 2016 # (6x+15)/(x^2-9)# Explanation: #(x^2-9)=(x+3)(x-3)# and #5/(x-3)=5(x+3)/((x-3)(x+3)) =(5x+15)/(x^2-9)# so #5/(x-3)+x/(x^2-9) = (5x+15)/(x^2-9)+x/(x^2-9) = (6x+15)/(x^2-9)# Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide #9x^2-16# by #3x+4#? How do you divide #\frac{x^2+2x-5}{x}#? How do you divide #\frac{x^2+3x+6}{x+1}#? How do you divide #\frac{x^4-2x}{8x+24}#? How do you divide: #(4x^2-10x-24)# divide by (2x+3)? How do you divide: #5a^2+6a-9# into #25a^4#? How do you simplify #(3m^22 + 27 mn - 12)/(3m)#? How do you simplify #(25-a^2) / (a^2 +a -30)#? See all questions in Division of Polynomials Impact of this question 1121 views around the world You can reuse this answer Creative Commons License