How do you simplify #5sqrt(1/3)#?

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Answer 1 · 2016-02-22T11:35:36

So #5 sqrt(1/3)" "=" "(5sqrt(3))/3#

I am not convinced this is a simplified version!

#5 sqrt(1/3)" " =" " 5 (sqrt(1))/sqrt(3)#

But #sqrt(1)=1" technically it is " +-1#

# 5/sqrt(3)" "..................................(1)#

It is common mathematical practise to try and not have any roots in the denominator. If possible!

Note that if we have #sqrt(3)/(sqrt(3) # it is the same value as 1

Multiply expression (1) by the value of 1 but in the form of#" "sqrt(3)/sqrt(3)#

#5/sqrt(3) xx sqrt(3)/sqrt(3)" "=" "(5sqrt(3))/3" ".........................(1_a)#

So #5 sqrt(1/3)" "=" "(5sqrt(3))/3#