How do you simplify $6 (2 p + 1)$ $6(2p+1)$ ?

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Answer 1 · 2016-04-22T11:57:56

$= 6 \times 2 p + 6 \times 1 = 12 p + 6$ $=6xx2p+6xx1=12p+6$

Answer 2 · 2016-04-22T12:03:45

$12 p + 6$ $12p+6$

Given: $6 (2 p + 1)$ $" "6(2p+1)$

$Using first principles$ $color(blue)("Using first principles")$

This is the same as $6 \times (2 p + 1)$ $6xx(2p+1)$

So you have 6 lots of $(2 p + 1)$ $(2p+1)$

Which means you have:

6 lots of $2 p$ $2p$ and 6 lots of $(+ 1)$ $(+1)$ which gives

$2 p + 2 p + 2 p + 2 p + 2 p + 2 p + 6$ $2p+2p+2p+2p+2p+2p + 6$

This is the same as: $12 p + 6$ $12p+6$
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$Shortcut method$ $color(blue)("Shortcut method")$

Multiply everything inside the brackets by 6 giving

$12 p + 6$ $12p+6$

How do you simplify 6(2p+1)6(2p+1)?