How do you simplify (-6+5i)(7-5i)(6+6i)? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer Καδήρ Κ. Jul 21, 2017 -102(1+i) Explanation: (-6+5i)(7-5i)(6+6i)= (-42+30i+35i-25i^2)(6+6i)= (-42+65i+25)(6+6i)= (-17+65i)(6+6i)= (-102-102i+390+390i^2)= -102(1+i) Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square (1+i)? What is the geometric interpretation of multiplying two complex numbers? What is the product of 3+2i and 1+7i? How do I use DeMoivre's theorem to solve z^3-1=0? How do I find the product of two imaginary numbers? How do you simplify (2+4i)(2-4i)? How do you multiply (-2-8i)(6+7i)? See all questions in Multiplication of Complex Numbers Impact of this question 1895 views around the world You can reuse this answer Creative Commons License