How do you simplify #6(-7+6i)(-4+2i)#? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer Binayaka C. Oct 13, 2017 #96 - 228i# Explanation: #6 (-7+6i)(-4+2i) = 6 ( 28 -14i -24i +12i^2) # #=6 ( 28 -38i -12 ) [i^2=-1] = 6( 16-38i) = 96 - 228i# #:. 6 (-7+6i)(-4+2i)=96 - 228i# [Ans] Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square #(1+i)#? What is the geometric interpretation of multiplying two complex numbers? What is the product of #3+2i# and #1+7i#? How do I use DeMoivre's theorem to solve #z^3-1=0#? How do I find the product of two imaginary numbers? How do you simplify #(2+4i)(2-4i)#? How do you multiply #(-2-8i)(6+7i)#? See all questions in Multiplication of Complex Numbers Impact of this question 4812 views around the world You can reuse this answer Creative Commons License