How do you simplify $(6i)(-2i)$ ?

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Answer 1 · 2016-10-21T16:31:58

$12$

We can rearrange this multiplication problem:

$(6i)(-2i)=(6*-2)(i*i)=-12i^2$

Recall the definition of $i$ , that it $i=sqrt(-1)$ . Squaring both sides shows that $i^2=-1$ . Thus

$-12i^2=-12(-1)=12$

How do you simplify (6i)(-2i)(6i)(-2i)?