# How do you simplify 6i(3+2i)?

Sep 16, 2016

$- 12 + 18 i$

#### Explanation:

We have: $6 i \left(3 + 2 i\right)$

Let's expand the parentheses:

$= \left(6 i\right) \left(3\right) + \left(6 i\right) \left(2 i\right)$

$= 18 i + 12 {i}^{2}$

Let's apply the fact that ${i}^{2} = - 1$:

$= 18 i + 12 \cdot - 1$

$= - 12 + 18 i$