# How do you simplify 7 3/8 + 1 1/16?

You getb the $\frac{3}{8}$ to the same denominator by multiplying with a 'disguised' $1$.
$= 7 + \left(\frac{3}{8} \times \frac{2}{2}\right) + 1 + \frac{1}{16}$
$= 7 + \frac{6}{16} + 1 + \frac{1}{16}$
$= 8 + \frac{7}{16} = 8 \frac{7}{16}$