How do you simplify #(7 - 6i)(2 - 3i)#?
1 Answer
Feb 21, 2016
-4 - 33i
Explanation:
first distribute brackets using FOIL ( or any method you use )
#(7 - 6i )(2 - 3i ) = 14 - 21i - 12i +18i^2# [Note that:
#i^2 = (sqrt-1)^2 = -1 # ]hence: 14 -21i - 12i
#+ 18i^2 = 14 -33i -18 = - 4 - 33i #
