How do you simplify #(-7i)(4i)(-1+3i)#?
1 Answer
Aug 23, 2016
Explanation:
distribute the bracket after multiplying the 2 terms outside the bracket.
#rArr-28i^2(-1+3i)#
#color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(a/a)|)))#
#rArr-28i^2(-1+3i)=28(-1+3i)=-28+84i#
