How do you simplify #7sqrt32#?

1 Answer
Apr 4, 2016

Answer:

#=28 sqrt2 #

Explanation:

#7 sqrt 32#

We first prime factorise #32# ( express a number as a product of its prime factors)

#sqrt 32 = sqrt ( 2 * 2 * 2 * 2 * 2 ) = sqrt (2^2 * 2^2 * 2) = 2 * 2 * sqrt2 = color(blue)(4sqrt2#

#7 sqrt 32 = 7 * (color(blue)(4sqrt2))#

#=28 sqrt2 #