How do you simplify $- 7 \sqrt{98}$ $-7sqrt98$ ?

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Answer 1 · 2018-03-25T20:24:31

$- 7 \sqrt{98} \Rightarrow - 49 \sqrt{2}$ $-7sqrt(98)rArr-49sqrt(2)$

Try to factor the radical so that it contains a perfect square.

In this case, we can factor:

$- 7 \sqrt{98} = - 7 \sqrt{49 \cdot 2}$ $-7sqrt(98)=-7sqrt(49*2)$

Now separate the radical into two terms and simplify:

$- 7 \sqrt{49 \cdot 2} = - 7 \sqrt{49} \sqrt{2} = - 7 (7) \sqrt{2} = - 49 \sqrt{2}$ $-7sqrt(49*2)=-7sqrt(49)sqrt(2)=-7(7)sqrt(2)=-49sqrt(2)$

How do you simplify -7sqrt98−7√98-7sqrt98?