How do you simplify #(8^(-1/2))^(-2/3)#?

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Answer 1 · 2016-06-16T16:26:50

#(8^(-1/2))^(-2/3)=2#

As #(a^m)^n=a^(mxxn)#

#(8^(-1/2))^(-2/3)#

= #8^((-1/2)xx(-2/3))#

= #8^(1/3)#

but #8=2^3#, hence above is equal to

= #(2^3)^(1/3)#

= #2^(3xx1/3)#

= #2^1=2#