How do you simplify #(8-3i)(8+3i)#?

Question

3545 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-08-10T17:57:31

#73#

#(8-3i)(8+3i)#

Use FOIL to distribute:
#8 * 8 = 64#

#8 * 3i = 24i#

#-3i * 8 = -24i#

#-3i * 3i = -9i^2#

Combine them together:
#64 + 24i - 24i - 9i^2#

Simplify:
#64 - 9i^2#

We know that #i^2 = -1#, so:
#64 - 9(-1)#

#64 + 9#

#73#

Hope this helps!