How do you simplify $(8p+8)/(2p^2-4p-6)$ ?

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Answer 1 · 2016-08-15T20:17:55

$= 4/(p-3)$

Factor numerator and denominator first.

$(8(p+1))/(2(p^2 -2p-3)) = (8(p+1))/(2(p-3)(p+1)$

$((cancel8^4)cancel(p+1))/(cancel2(p-3)cancel(p+1)) =$

$= 4/(p-3)$

How do you simplify (8p+8)/(2p^2-4p-6)(8p+8)/(2p^2-4p-6)?