How do you simplify #(8p+8)/(2p^2-4p-6)#? Algebra Rational Equations and Functions Division of Polynomials 1 Answer EZ as pi Aug 15, 2016 #= 4/(p-3)# Explanation: Factor numerator and denominator first. #(8(p+1))/(2(p^2 -2p-3)) = (8(p+1))/(2(p-3)(p+1)# #((cancel8^4)cancel(p+1))/(cancel2(p-3)cancel(p+1)) =# #= 4/(p-3)# Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide #9x^2-16# by #3x+4#? How do you divide #\frac{x^2+2x-5}{x}#? How do you divide #\frac{x^2+3x+6}{x+1}#? How do you divide #\frac{x^4-2x}{8x+24}#? How do you divide: #(4x^2-10x-24)# divide by (2x+3)? How do you divide: #5a^2+6a-9# into #25a^4#? How do you simplify #(3m^22 + 27 mn - 12)/(3m)#? How do you simplify #(25-a^2) / (a^2 +a -30)#? See all questions in Division of Polynomials Impact of this question 1353 views around the world You can reuse this answer Creative Commons License