How do you simplify #(8x+3y)(2x-y) #?

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Answer 1 · 2016-08-18T08:24:58

#16x^2-2xy-3y^2#

Given:#" "color(blue)((8x+3y)color(brown)((2x-y)#

Multiply everything in the right hand side (RHS) bracket by everything in the left hand side (LHS) bracket.

Note that the + from #+3y# follows the #3y#.

#color(brown)(color(blue)(8x)(2x-y)color(blue)(" "+3y)(2x-y) # giving:

#color(white)(.)#

#16x^2color(magenta)(-8xy" "+6xy)-3y^2#

#color(white)(.)#

but #color(magenta)(-8xy+6xy)color(green)(=-2xy)#

#16x^2color(green)(-2xy)-3y^2#