How do you simplify and divide (y^5+32)(y+2)^-1(y5+32)(y+2)1?

1 Answer
Oct 30, 2016

Let's start by simplifying, using the rule a^-1 = 1/aa1=1a.

=> (y^5 + 32)/(y + 2)y5+32y+2

This is now a division problem, that can be done by either synthetic or long division. I will do it using synthetic division.

-2"_|1 0 0 0 0 32"2_|1 0 0 0 0 32
" -2 4 -8 16 -32" -2 4 -8 16 -32
"-----------------------------------------------------------"-----------------------------------------------------------
" 1 -2 4 -8 16 0" 1 -2 4 -8 16 0

So, the quotient is y^4 - 2y^3 + 4y^2 - 8y + 16y42y3+4y28y+16.

This cannot be factored further, if you check using the rational root theorem and the remainder theorem.

Hopefully this helps!