How do you simplify and find the excluded value of #(x^2 – 3x + 2)/( 7x – 14) div(x^2 – 1)/(7x + 7)#?

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Answer 1 · 2016-08-30T19:50:43

Your expression simplifies to #1#, with restrictions being #x!=+-1, 2#.

Factor everything:

#=>((x - 2)(x - 1))/(7(x - 2)) xx (7(x + 1))/((x + 1)(x - 1))#

Cancel using the property #a/a = 1, a !=0#.

#=>1#

Now, state the restrictions on the variable. These will occur when the denominator equals #0#.

#x!=-1, 1, 2#

Hopefully this helps!