How do you simplify and find the excluded values for #(2a^2+10a)/(3a^2+15a)#?

1 Answer
Sep 13, 2015

Answer:

Expression simplifies to #2/3 and a!=0 and a!=-5#

Explanation:

Factorize top and bottom by taking out a common factor to obtain

#(2a(a+5))/(3a(a+5)#

We now cancel to yield #2/3#

Now the excluded values, also called the restrictions, are values that would make the denominator equal to zero as this would be undefined.
These values would be #a=0 and a=-5#