How do you simplify and find the excluded values of #5/(7z+5)#?
The given rational function is already in simplest form. The denominator cannot be factorised, which would allow cancelling and thus simplification.
The excluded value is the value of z that would make the denominator equal to zero.
#5/0#as we cannot divide by zero, this would be undefined.
To find the excluded value equate the denominator to zero and solve for z.
solve : 7z + 5 = 0
#rArrz=-5/7" is the excluded value"#