How do you simplify and write #(4x^-4y^2)^-3# with positive exponents?

1 Answer
Jul 10, 2018

Answer:

#x^12/(64y^6)#

Explanation:

Our expression is the same as

#1/(4x^-4y^2)^3#

#4^3=color(blue)(64)#, #(x^-4)^3=x^(-4*3)=color(blue)(x^(-12))#, #(y^2)^3-y^(2*3)=color(blue)(y^6)#

With this in mind, we now have the following:

#1/(64x^-12y^6)#

We can make the negative exponent positive by bringing it to the numerator. We now have

#x^12/(64y^6)#

Hope this helps!