How do you simplify (b+4)/(2b^2+5b-12)?

$\frac{1}{2 b - 3}$
$\frac{b + 4}{2 {b}^{2} + 5 b - 12}$ = $\frac{b + 4}{\left(2 b - 3\right) \left(b + 4\right)}$
The b+4 cancels to leave $\frac{1}{2 b - 3}$