Question

How do you simplify `-\frac { 28x y ^ { 0} z ^ { 4} } { 14x ^ { 7} y ^ { 5} z ^ { 4} }`?

Answer 1

`(28xy^0z^4)/(14x^7y^5z^4)=2/(x^6y^5)`

Explanation:

`(28xy^0z^4)/(14x^7y^5z^4)`

= `28/14xx x^1/x^7xxy^0/y^5xxz^4/z^4`

= `2xx x^((1-7))xxy^((0-5))xxz^((4-4))`

= `2xx x^(-6)xxy^(-5)xxz^0`

= `2xx1/x^6xx1/y^5xx1`

= `2/(x^6y^5)`