How do you simplify #\frac { \sqrt { 63} + 24} { 3}#?

2 Answers
Apr 5, 2018

Answer:

#8+sqrt7#

Explanation:

#(sqrt63+24)/3#
=#((sqrt9xxsqrt7)+24)/3#
=#((3xxsqrt7)+24)/3#
=#(3(sqrt7+8))/3#
=#8+sqrt7#

Apr 5, 2018

Answer:

#sqrt(7) + 8#

Explanation:

  1. First, you would simplify the square root of #63# by splitting it into #sqrt(7)# multiplied by #sqrt(9)# (because #9xx7=63#).
  2. Then #sqrt(9)# reduces to #3#, so you have #3sqrt(7) + 24# (ignoring the dividing by #3# for now).
  3. Then take #3sqrt(7) + 24# and divide each term by #3#.
  4. The #3#'s in #3sqrt(7)# would cancel and give you #sqrt(7)#.
  5. The #24# divided by #3# would give you #8#.
  6. So your final answer is #sqrt(7) + 8#