How do you simplify #i^109#?
1 Answer
Dec 12, 2015
Explanation:
We will be using the following:

#(x^a)^b = x^(ab)# 
#i^2 = 1#
Because
Using this, we can take
While the above suffices for the given problem, it is also applicable to integers which are much larger, or not multiples of
We can write
So, applying this to our problem: