How do you simplify #(i)*11+(8i)#?
1 Answer
Aug 3, 2016
19i
Explanation:
#(i).11=ixx11=11i# Hence to simplify 11i + 8i , collect 'like terms'
#rArr11i+8i=19i#
19i
#(i).11=ixx11=11i# Hence to simplify 11i + 8i , collect 'like terms'
#rArr11i+8i=19i#