How do you simplify $i^35$ ?

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Answer 1 · 2015-11-16T12:34:32

$i^35 = -i$

$i^2=-1$
$i^4 = (i^2)^2 = (-1)^2 = +1$

$i^35 = i^32*i^2*i$

$= (i^4)^8*i^2*i$

$=1^8*(-1)*i$

$=-i$

How do you simplify i^35i^35?