Question

How do you simplify `i^35`?

Answer 1

`i^35 = -i`

Explanation:

`i^2=-1`
`i^4 = (i^2)^2 = (-1)^2 = +1`

`i^35 = i^32*i^2*i`

`= (i^4)^8*i^2*i`

`=1^8*(-1)*i`

`=-i`