How do you simplify i^803? Precalculus Complex Numbers in Trigonometric Form Powers of Complex Numbers 1 Answer Alan P. ยท Nam D. Mar 9, 2018 i^803=color(red)(-i) Explanation: i^1=i i^2=-1 (definition) i^3=(-1)xxi=-i i^4=(-1)xx(-1)=1 i^803=i^800 * i^3 color(white)("XX")=(i^4)^200 * i^3 color(white)("XX")=1^200 * (-i) color(white)("XX") =1xx(-i) color(white)("XX")=-i Answer link Related questions How do I use DeMoivre's theorem to find (1+i)^5? How do I use DeMoivre's theorem to find (1-i)^10? How do I use DeMoivre's theorem to find (2+2i)^6? What is i^2? What is i^3? What is i^4? How do I find the value of a given power of i? How do I find the nth power of a complex number? How do I find the negative power of a complex number? Write the complex number i^17 in standard form? See all questions in Powers of Complex Numbers Impact of this question 1648 views around the world You can reuse this answer Creative Commons License
