# How do you simplify log_3 3 + log_2 64?

Jun 14, 2016

${\log}_{3} \left(3\right) + {\log}_{2} \left(64\right) = 7$

#### Explanation:

We use identities ${\log}_{a} a = 1$ and ${\log}_{a} \left({a}^{m}\right) = m$

Hence ${\log}_{3} \left(3\right) + {\log}_{2} \left(64\right)$

= ${\log}_{3} \left(3\right) + {\log}_{2} \left({2}^{6}\right)$

= $1 + 6 = 7$