How do you simplify #(q^2+14q+48)/(q^2+q-30)#?

1 Answer
Oct 14, 2015

#(q+8)/(q-5)# for #q != -6# and #q != 5#

Explanation:

Notice that
#q^2+14q+48 = (q+6)(q+8)#
and
#q^2+q-30 = (q+6)(q-5)#

Therefore,
#(q^2+14q+48)/(q^2+q-30) = ((q+6)(q+8))/((q+6)(q-5))#

This expression is not defined for
#q = -6# and #q = 5#

For all other values of #q# we can reduce it by #q+6# to
#(q+8)/(q-5)#