# How do you simplify root3(16/27)?

Jul 28, 2016

$\sqrt[3]{\frac{16}{27}} = \frac{\sqrt[3]{16}}{3}$

#### Explanation:

$16$ is not a cube. so it does not have a rational cube root.

However, $27$ is a cube. $\sqrt[3]{27} = 3$

In $\sqrt[3]{\frac{16}{27}}$ find the roots that we can......

$\sqrt[3]{\frac{16}{27}} = \frac{\sqrt[3]{16}}{3}$