How do you simplify #root3(351 )#?

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Answer 1 · 2016-12-23T03:43:35

First factorize 351. we get 351 = 333*13.

Now #root(3) 351 = (351)^(1/3) = (3.3.3.13)^(1/3)#

= #[3^1 . 3^1 . 3^1 .13]^(1/3) #

=#[3^(1+1+1) . 13]^(1/3)#

=#[3^3 . 13]^(1/3)#

= #[3^(3*1/3) . 13]^(1/3)#

=#3root(3) 13#